Finitarily Bernoulli factors are dense
Stephen Shea
Fundamenta Mathematicae, Tome 220 (2013), p. 49-54 / Harvested from The Polish Digital Mathematics Library

It is not known if every finitary factor of a Bernoulli scheme is finitarily isomorphic to a Bernoulli scheme (is finitarily Bernoulli). In this paper, for any Bernoulli scheme X, we define a metric on the finitary factor maps from X. We show that for any finitary map f: X → Y, there exists a sequence of finitary maps fₙ: X → Y(n) that converges to f, where each Y(n) is finitarily Bernoulli. Thus, the maps to finitarily Bernoulli factors are dense. Let (X(n)) be a sequence of Bernoulli schemes such that each Y(n) is finitarily isomorphic to X(n). Let X' be a Bernoulli scheme with the same entropy as Y. Then we also show that (X(n)) can be chosen so that there exists a sequence of finitary maps to the X(n) that converges to a finitary map to X'.

Publié le : 2013-01-01
EUDML-ID : urn:eudml:doc:283344
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     author = {Stephen Shea},
     title = {Finitarily Bernoulli factors are dense},
     journal = {Fundamenta Mathematicae},
     volume = {220},
     year = {2013},
     pages = {49-54},
     zbl = {06221012},
     language = {en},
     url = {http://dml.mathdoc.fr/item/bwmeta1.element.bwnjournal-article-doi-10_4064-fm223-1-3}
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Stephen Shea. Finitarily Bernoulli factors are dense. Fundamenta Mathematicae, Tome 220 (2013) pp. 49-54. http://gdmltest.u-ga.fr/item/bwmeta1.element.bwnjournal-article-doi-10_4064-fm223-1-3/