The Diophantine equation $u(u+1)(u+2)(u+3)=v(v+1)(v+2)$.
Boyd, David W. ; Kisilevsky, H. H.
Pacific J. Math., Tome 43 (1972) no. 3, p. 23-32 / Harvested from Project Euclid
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Publié le : 1972-05-14
Classification:  10B10 
@article{1102968817,
     author = {Boyd, David W. and Kisilevsky, H. H.},
     title = {The Diophantine equation $u(u+1)(u+2)(u+3)=v(v+1)(v+2)$.},
     journal = {Pacific J. Math.},
     volume = {43},
     number = {3},
     year = {1972},
     pages = { 23-32},
     language = {en},
     url = {http://dml.mathdoc.fr/item/1102968817}
}

Boyd, David W.; Kisilevsky, H. H. The Diophantine equation $u(u+1)(u+2)(u+3)=v(v+1)(v+2)$.. Pacific J. Math., Tome 43 (1972) no. 3, pp.  23-32. http://gdmltest.u-ga.fr/item/1102968817/