Let X be an hereditary subspace of the Polish space of real sequences, i.e. a subspace such that [x = (xₙ)ₙ ∈ X and ∀n, |yₙ| ≤ |xₙ|] ⇒ y = (yₙ)ₙ ∈ X. Does X admit a complete metric compatible with its vector structure? We have two results: ∙ If such an X has a complete metric δ, there exists a unique pair (E,F) of hereditary subspaces with E ⊆ X ⊆ F, (E,δ) complete separable, and F complete maximal in a strong sense. On E and F, the metrics have a simple form, and the spaces E are Borel (Π₃⁰ or Σ₂⁰) in . In particular, if X is separable, then X = E. ∙ If X is an hereditary space, analytic as a subset of , we can find a subspace of X strongly isomorphic to the space c₀₀ of finite sequences, or we can find a pair (E,F) and a metric with the same properties around X. If X is Σ₃⁰ in , we get a complete trichotomy describing the possible topologies of X, which makes precise a result of [C], but for general X’s, there are examples of various situations.
@article{bwmeta1.element.bwnjournal-article-doi-10_4064-fm168-3-1, author = {Pierre Casevitz}, title = {Espaces de suites r\'eelles compl\`etement m\'etrisables}, journal = {Fundamenta Mathematicae}, volume = {167}, year = {2001}, pages = {199-235}, language = {fra}, url = {http://dml.mathdoc.fr/item/bwmeta1.element.bwnjournal-article-doi-10_4064-fm168-3-1} }
Pierre Casevitz. Espaces de suites réelles complètement métrisables. Fundamenta Mathematicae, Tome 167 (2001) pp. 199-235. http://gdmltest.u-ga.fr/item/bwmeta1.element.bwnjournal-article-doi-10_4064-fm168-3-1/