$A \geq B \geq {0}$ iff $\left( {B^r A^p B^r} \right)^{1/q} \geq B^{\left( {p + 2r} \right)/q} $ for $r \geq {0},p \geq{0},q \geq 1$ with $\left( {1 + 2r} \right)q \geq p + 2r$
Furuta, Takayuki
Proc. Japan Acad. Ser. A Math. Sci., Tome 63 (1987) no. 9, p. 4-6 / Harvested from Project Euclid
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Publié le : 1987-05-15
Classification:  47A60,  15A45 
@article{1195514017,
     author = {Furuta, Takayuki},
     title = {$A \geq B \geq {0}$ iff $\left( {B^r A^p B^r} \right)^{1/q} \geq B^{\left( {p + 2r} \right)/q} $ for $r \geq {0},p \geq{0},q \geq 1$ with $\left( {1 + 2r} \right)q \geq p + 2r$},
     journal = {Proc. Japan Acad. Ser. A Math. Sci.},
     volume = {63},
     number = {9},
     year = {1987},
     pages = { 4-6},
     language = {en},
     url = {http://dml.mathdoc.fr/item/1195514017}
}

Furuta, Takayuki. $A \geq B \geq {0}$ iff $\left( {B^r A^p B^r} \right)^{1/q} \geq B^{\left( {p + 2r} \right)/q} $ for $r \geq {0},p \geq{0},q \geq 1$ with $\left( {1 + 2r} \right)q \geq p + 2r$. Proc. Japan Acad. Ser. A Math. Sci., Tome 63 (1987) no. 9, pp.  4-6. http://gdmltest.u-ga.fr/item/1195514017/