The quantifier $Q^{m,n}$ binds $m + n$ variables. In the $\kappa$-interpretation $M \models Q^{m,n} \bar{x}, \bar{y}\phi\bar{x}, \bar{y}$ means that there is a $\kappa$-powered proper subset $X$ of $|M|$ such that whenever $\bar{a} \in^mX$ and $\bar{b} \in^n\tilde{X}$ then $M \models \phi\bar{a}, \bar{b}$. If $\sigma \in L^{m,n}$ has a model in the $\kappa$-interpretation does it have a model in the $\lambda$-interpretation? For $\sigma \in L^{1,1}, \kappa$ regular and uncountable, and $\lambda = \omega_1$ the answer is yes.